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(R)=44R-0.01R^2
We move all terms to the left:
(R)-(44R-0.01R^2)=0
We get rid of parentheses
0.01R^2-44R+R=0
We add all the numbers together, and all the variables
0.01R^2-43R=0
a = 0.01; b = -43; c = 0;
Δ = b2-4ac
Δ = -432-4·0.01·0
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-43}{2*0.01}=\frac{0}{0.02} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+43}{2*0.01}=\frac{86}{0.02} =4300 $
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